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🚨 MAJOR BREAKING: Premier League confirm an independent Commission has found Manchester City GUILTY OF ALL CHARGES related to serious breaches of the Premier League’s financial rules over a nine-season period, and the majority of charges in relation to its failure to co-operate with the League’s investigation. The club has the right to appeal the independent Commission’s findings and has until Friday 2 October to exercise that right. The Premier League Board’s intention is that the full process (including any appeals and publication of relevant decisions) is concluded as soon as possible. The independent Commission found that between Seasons 2009/10 and 2017/18: - Manchester City arranged ‘sham’ contracts (which misrepresented the true agreement between the parties) with a number of its commercial partners, as well as relying on ‘sham’ agreements with others, to artificially inflate the club’s revenues and reduce its costs - The club filed misstated accounts and concealed the true state of its finances from its auditors and football regulators - Manchester City was significantly in breach of both the Premier League’s and UEFA’s spending limits - During the Premier League’s investigation, Manchester City committed multiple breaches of its duties of co-operation and utmost good faith towards the League (three of the four alleged breaches were upheld)
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Token2049 期间,「BNB Chain Super Meetup Singapore」将于新加坡举行, 活动将围绕 BNB Chain 生态展开,现场设有交流、互动与 networking 环节~ 🎟 报名链接: 新加坡见!🙌
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agencies will ruin ur account, make u earn less AND make u pay them a shit ton of money btw.
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格局不了一点,昨天粉丝还问我怎么老跳车,闪迪这波从1860开始空,本来想一直拿到现在,幸亏中间跳车了。 事实证明,不跳车狗庄就真能不做人,大饼以太更畜生,要走哪个方向必然先7插针扫一下反向。
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有什么用,我看注册得这么热闹,好像没看到任何一个有价值的应用场景。
X友们,你们的Apple Music订阅了哪个区?
Apple Music 中国区涨价到12元/月了,看到扣费通知了我才晓得
保持总数10一定之下(一个元素集合,即空间),取映射f: 10→(N, 10-N),g: 10-N→N,使得这两个映射的某种复合为恒等映射。 即第一个操作是分割,第二个操作是取补集 为了保证取补的操作是合法的,补上一点空点,即无所谓的量 具体数学细节的补充是简单的 好的,如果你不是数学系的人多半是听不懂的,翻译成人话就是……你拿10个出来,全都翻个面,结束
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一道智商检测题(评论区公布答案)。 100 枚硬币,两面分别是红色和蓝色,可以翻面,初始 10 枚红色向上,90 枚蓝色向上,堆成一堆,但你不知道具体某一硬币的具体情况,你需要分成两堆,需要两堆红色硬币向上的数量相同。
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